Sonnet № 77262
Why you don't fall through the floor
Schrödingerâs equation: -(ħ²/2M)grad²Ï(x,y,z) + VÏ(x,y,z) = EÏ(z,y,z)
For a particle in a box:
V = 0 if 0 < x,y,x < a
= â otherwise
Try a solution of the form Ï = Nsin(2Ïlx/a)sin(2Ïmy/a)sin(2Ïnz/a)
Where N is the normalisation factor.
Ï must go to zero at x,y,z = a, therefore l,m,n are integers.
So, E = -(1/2M)(2Ïħ/a)²(l² + m² + n²)
Now, pressure P = âE/âV
And dV = d³a = d(a³) = 3a²da
Therefore P = (1/3a²)âE/âa
This is quantum pressure.
46 comments
will make it really elemental for this holiday season no need to invite the neighboors they will get a lil -bit wink..ahem quantro what the hell..be generous, all the stolish you want. As 33 a dash,H1 yep,He2 what the hell laugh a bit,N7 a bit expensive but why not,Pu94 a
pinch of criptonite you'll fly anyhow just to be sure extra momentum now don't bother to shake, make it pretty and light it. pressureP=Boom now that's how to be a particle in a box happy reincarnation!!I'll drink eggnog with a shot of 151 hold the extras, a quantum 10
PS: Play with the rectangular "holes" first.
Assume an equilateral triangle shaped manhole cover, with sides of length x. Show that if we are to be sure the manhole cover CAN fall down the manhole, then its thickness must not exceed
(x/4)*(2*(root 3) - 3)
Indeed, if this result is correct, and we assume a reasonable value for x (say 1m?), then provided its thickness does not exceed about 11.6 cm, it WILL be able to fall down the manhole.
Is 11.6cm a spectacularly thick manhole cover? I daresay it is not, though more research in this field is DESPERATELY needed.
Good day to you, Sir!
45° and 0°...??? What more am I to conclude from you here? Remember this: Gravity is our friend, always has been, always will be. If you drop a golf ball straight into a hole, what is the angle of approach? This is the second question on the test. (Your scholarship is at stake.)
You're "nadda-gonna" give Dave the answer, are you?
Ok, an equalateral triangle can fall through it's hole. At least I don't award jobs based on the ability to instantly solve crappy brainteasers. Look, you should always work on this principle: I am the cleverest person in the world, therefore anything I say is the best thing to say given the circumstances.
No doubt you'll agree that his is a very sorry tale, indeed.
Good day.
(dV/da) = 3a²
So dV = 3a²da.
But how do you get dV = d³a ? d³a = d(d(da)), doesn't it?
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